🔌 PCB Conductor Current
Given a trace geometry, find current capacity, resistance, voltage drop, and power dissipation. Based on IPC-2221.
Layer Type
External traces dissipate heat to air (k = 0.048). Internal traces are thermally isolated (k = 0.024).
$$A = W \times T \qquad I_\text{max} = k\,\Delta T^{0.44}\,A^{0.725}$$
A is cross-section in mil². k = 0.048 external, 0.024 internal (IPC-2221).
1 oz/ft² ≈ 35 µm ≈ 1.378 mil
Used to calculate voltage drop & power (if provided)
⚠ Please enter trace width and copper weight.
Results
Copper Weight Reference
| oz/ft² | Thickness (µm) | Thickness (mil) |
|---|---|---|
| 0.5 oz | 17.5 µm | 0.69 mil |
| 1 oz | 35 µm | 1.38 mil |
| 2 oz | 70 µm | 2.76 mil |
| 3 oz | 105 µm | 4.13 mil |